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ScienceAges 10-12

Series & parallel resistor networks

Calculate equivalent resistance for resistors in series (R₁ + R₂) or in parallel ((R₁ × R₂) ÷ (R₁ + R₂)). Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 10-12

Series & parallel resistor networks

Take your time. Show your thinking.

  1. 1. Two resistors of 18 Ω and 90 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    +−R
    Parallel: 18 Ω ∥ 90 Ω · 1/R_eq = 1/18 + 1/90
  2. 2. Two resistors of 24 Ω and 72 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    +−R
    Parallel: 24 Ω ∥ 72 Ω · 1/R_eq = 1/24 + 1/72
  3. 3. Two resistors of 16 Ω and 48 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    +−R
    Parallel: 16 Ω ∥ 48 Ω · 1/R_eq = 1/16 + 1/48
  4. 4. Two resistors of 3 Ω and 3 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 3 Ω, R₂ = 3 Ω · R_eq = R₁ + R₂ = ?
  5. 5. Two resistors of 20 Ω and 14 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 20 Ω, R₂ = 14 Ω · R_eq = R₁ + R₂ = ?
  6. 6. Two resistors of 6 Ω and 8 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 6 Ω, R₂ = 8 Ω · R_eq = R₁ + R₂ = ?
  7. 7. Two resistors of 30 Ω and 60 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    +−R
    Parallel: 30 Ω ∥ 60 Ω · 1/R_eq = 1/30 + 1/60
  8. 8. Two resistors of 20 Ω and 60 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    +−R
    Parallel: 20 Ω ∥ 60 Ω · 1/R_eq = 1/20 + 1/60
  9. 9. Two resistors of 20 Ω and 19 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 20 Ω, R₂ = 19 Ω · R_eq = R₁ + R₂ = ?
  10. 10. Two resistors of 8 Ω and 2 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 8 Ω, R₂ = 2 Ω · R_eq = R₁ + R₂ = ?
  11. 11. Two resistors of 23 Ω and 14 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 23 Ω, R₂ = 14 Ω · R_eq = R₁ + R₂ = ?
  12. 12. Two resistors of 8 Ω and 17 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    +−R
    Series: R₁ = 8 Ω, R₂ = 17 Ω · R_eq = R₁ + R₂ = ?
12 questions · Seed 55 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 10-12

Series & parallel resistor networks

Answers and reasoning. Review before teaching.

  1. 1. Two resistors of 18 Ω and 90 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    15 Ω

    For two parallel resistors, R_eq = (18 × 90) ÷ (18 + 90) = 1620 ÷ 108 = 15 Ω.

  2. 2. Two resistors of 24 Ω and 72 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    18 Ω

    For two parallel resistors, R_eq = (24 × 72) ÷ (24 + 72) = 1728 ÷ 96 = 18 Ω.

  3. 3. Two resistors of 16 Ω and 48 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    12 Ω

    For two parallel resistors, R_eq = (16 × 48) ÷ (16 + 48) = 768 ÷ 64 = 12 Ω.

  4. 4. Two resistors of 3 Ω and 3 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    6 Ω

    In a series circuit, resistances add directly: R_eq = 3 Ω + 3 Ω = 6 Ω.

  5. 5. Two resistors of 20 Ω and 14 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    34 Ω

    In a series circuit, resistances add directly: R_eq = 20 Ω + 14 Ω = 34 Ω.

  6. 6. Two resistors of 6 Ω and 8 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    14 Ω

    In a series circuit, resistances add directly: R_eq = 6 Ω + 8 Ω = 14 Ω.

  7. 7. Two resistors of 30 Ω and 60 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    20 Ω

    For two parallel resistors, R_eq = (30 × 60) ÷ (30 + 60) = 1800 ÷ 90 = 20 Ω.

  8. 8. Two resistors of 20 Ω and 60 Ω are connected in parallel. Using R_eq = (R₁ × R₂) ÷ (R₁ + R₂), calculate their equivalent resistance.

    15 Ω

    For two parallel resistors, R_eq = (20 × 60) ÷ (20 + 60) = 1200 ÷ 80 = 15 Ω.

  9. 9. Two resistors of 20 Ω and 19 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    39 Ω

    In a series circuit, resistances add directly: R_eq = 20 Ω + 19 Ω = 39 Ω.

  10. 10. Two resistors of 8 Ω and 2 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    10 Ω

    In a series circuit, resistances add directly: R_eq = 8 Ω + 2 Ω = 10 Ω.

  11. 11. Two resistors of 23 Ω and 14 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    37 Ω

    In a series circuit, resistances add directly: R_eq = 23 Ω + 14 Ω = 37 Ω.

  12. 12. Two resistors of 8 Ω and 17 Ω are connected in series across a circuit. Calculate their combined equivalent resistance.

    25 Ω

    In a series circuit, resistances add directly: R_eq = 8 Ω + 17 Ω = 25 Ω.

12 questions · Seed 55 · Age guidance, not curriculum certification