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ScienceAges 16-18

Potential divider circuits

Apply the potential divider equation V_out = (R₂ ÷ (R₁ + R₂)) × V_in across two series resistors connected to a DC source. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

Potential divider circuits

Take your time. Show your thinking.

  1. 1. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 18 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 16 V · R₁ = 6 Ω, R₂ = 18 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  2. 2. In a potential divider circuit connected to a 72 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 72 V · R₁ = 12 Ω, R₂ = 20 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  3. 3. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 21 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 32 V · R₁ = 21 Ω, R₂ = 35 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  4. 4. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 16 V · R₁ = 12 Ω, R₂ = 36 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  5. 5. In a potential divider circuit connected to a 50 V DC supply, resistor R₁ = 4 Ω and resistor R₂ = 16 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 50 V · R₁ = 4 Ω, R₂ = 16 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  6. 6. In a potential divider circuit connected to a 20 V DC supply, resistor R₁ = 2 Ω and resistor R₂ = 2 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 20 V · R₁ = 2 Ω, R₂ = 2 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  7. 7. In a potential divider circuit connected to a 15 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 15 V · R₁ = 6 Ω, R₂ = 24 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  8. 8. In a potential divider circuit connected to a 42 V DC supply, resistor R₁ = 18 Ω and resistor R₂ = 45 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 42 V · R₁ = 18 Ω, R₂ = 45 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  9. 9. In a potential divider circuit connected to a 56 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 56 V · R₁ = 12 Ω, R₂ = 20 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  10. 10. In a potential divider circuit connected to a 28 V DC supply, resistor R₁ = 4 Ω and resistor R₂ = 12 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 28 V · R₁ = 4 Ω, R₂ = 12 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  11. 11. In a potential divider circuit connected to a 12 V DC supply, resistor R₁ = 8 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 12 V · R₁ = 8 Ω, R₂ = 24 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  12. 12. In a potential divider circuit connected to a 10 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 3 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 10 V · R₁ = 3 Ω, R₂ = 3 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
12 questions · Seed 70 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

Potential divider circuits

Answers and reasoning. Review before teaching.

  1. 1. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 18 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    12 V

    Total resistance R₁ + R₂ = 6 + 18 = 24 Ω. Potential difference across R₂ is V_out = (18 ÷ 24) × 16 V = 12 V.

  2. 2. In a potential divider circuit connected to a 72 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    45 V

    Total resistance R₁ + R₂ = 12 + 20 = 32 Ω. Potential difference across R₂ is V_out = (20 ÷ 32) × 72 V = 45 V.

  3. 3. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 21 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    20 V

    Total resistance R₁ + R₂ = 21 + 35 = 56 Ω. Potential difference across R₂ is V_out = (35 ÷ 56) × 32 V = 20 V.

  4. 4. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    12 V

    Total resistance R₁ + R₂ = 12 + 36 = 48 Ω. Potential difference across R₂ is V_out = (36 ÷ 48) × 16 V = 12 V.

  5. 5. In a potential divider circuit connected to a 50 V DC supply, resistor R₁ = 4 Ω and resistor R₂ = 16 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    40 V

    Total resistance R₁ + R₂ = 4 + 16 = 20 Ω. Potential difference across R₂ is V_out = (16 ÷ 20) × 50 V = 40 V.

  6. 6. In a potential divider circuit connected to a 20 V DC supply, resistor R₁ = 2 Ω and resistor R₂ = 2 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    10 V

    Total resistance R₁ + R₂ = 2 + 2 = 4 Ω. Potential difference across R₂ is V_out = (2 ÷ 4) × 20 V = 10 V.

  7. 7. In a potential divider circuit connected to a 15 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    12 V

    Total resistance R₁ + R₂ = 6 + 24 = 30 Ω. Potential difference across R₂ is V_out = (24 ÷ 30) × 15 V = 12 V.

  8. 8. In a potential divider circuit connected to a 42 V DC supply, resistor R₁ = 18 Ω and resistor R₂ = 45 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    30 V

    Total resistance R₁ + R₂ = 18 + 45 = 63 Ω. Potential difference across R₂ is V_out = (45 ÷ 63) × 42 V = 30 V.

  9. 9. In a potential divider circuit connected to a 56 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    35 V

    Total resistance R₁ + R₂ = 12 + 20 = 32 Ω. Potential difference across R₂ is V_out = (20 ÷ 32) × 56 V = 35 V.

  10. 10. In a potential divider circuit connected to a 28 V DC supply, resistor R₁ = 4 Ω and resistor R₂ = 12 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    21 V

    Total resistance R₁ + R₂ = 4 + 12 = 16 Ω. Potential difference across R₂ is V_out = (12 ÷ 16) × 28 V = 21 V.

  11. 11. In a potential divider circuit connected to a 12 V DC supply, resistor R₁ = 8 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    9 V

    Total resistance R₁ + R₂ = 8 + 24 = 32 Ω. Potential difference across R₂ is V_out = (24 ÷ 32) × 12 V = 9 V.

  12. 12. In a potential divider circuit connected to a 10 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 3 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    5 V

    Total resistance R₁ + R₂ = 3 + 3 = 6 Ω. Potential difference across R₂ is V_out = (3 ÷ 6) × 10 V = 5 V.

12 questions · Seed 70 · Age guidance, not curriculum certification