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ScienceAges 16-18

Potential divider circuits

Apply the potential divider equation V_out = (R₂ ÷ (R₁ + R₂)) × V_in across two series resistors connected to a DC source. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

Potential divider circuits

Take your time. Show your thinking.

  1. 1. In a potential divider circuit connected to a 40 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 40 V · R₁ = 12 Ω, R₂ = 36 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  2. 2. In a potential divider circuit connected to a 50 V DC supply, resistor R₁ = 8 Ω and resistor R₂ = 32 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 50 V · R₁ = 8 Ω, R₂ = 32 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  3. 3. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 5 Ω and resistor R₂ = 15 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 32 V · R₁ = 5 Ω, R₂ = 15 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  4. 4. In a potential divider circuit connected to a 70 V DC supply, resistor R₁ = 15 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 70 V · R₁ = 15 Ω, R₂ = 35 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  5. 5. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 32 V · R₁ = 3 Ω, R₂ = 9 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  6. 6. In a potential divider circuit connected to a 6 V DC supply, resistor R₁ = 11 Ω and resistor R₂ = 11 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 6 V · R₁ = 11 Ω, R₂ = 11 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  7. 7. In a potential divider circuit connected to a 28 V DC supply, resistor R₁ = 11 Ω and resistor R₂ = 33 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 28 V · R₁ = 11 Ω, R₂ = 33 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  8. 8. In a potential divider circuit connected to a 42 V DC supply, resistor R₁ = 10 Ω and resistor R₂ = 25 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 42 V · R₁ = 10 Ω, R₂ = 25 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  9. 9. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 16 V · R₁ = 9 Ω, R₂ = 9 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  10. 10. In a potential divider circuit connected to a 20 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 14 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 20 V · R₁ = 6 Ω, R₂ = 14 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  11. 11. In a potential divider circuit connected to a 35 V DC supply, resistor R₁ = 24 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 35 V · R₁ = 24 Ω, R₂ = 36 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  12. 12. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 16 V · R₁ = 3 Ω, R₂ = 9 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
12 questions · Seed 60 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

Potential divider circuits

Answers and reasoning. Review before teaching.

  1. 1. In a potential divider circuit connected to a 40 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    30 V

    Total resistance R₁ + R₂ = 12 + 36 = 48 Ω. Potential difference across R₂ is V_out = (36 ÷ 48) × 40 V = 30 V.

  2. 2. In a potential divider circuit connected to a 50 V DC supply, resistor R₁ = 8 Ω and resistor R₂ = 32 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    40 V

    Total resistance R₁ + R₂ = 8 + 32 = 40 Ω. Potential difference across R₂ is V_out = (32 ÷ 40) × 50 V = 40 V.

  3. 3. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 5 Ω and resistor R₂ = 15 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    24 V

    Total resistance R₁ + R₂ = 5 + 15 = 20 Ω. Potential difference across R₂ is V_out = (15 ÷ 20) × 32 V = 24 V.

  4. 4. In a potential divider circuit connected to a 70 V DC supply, resistor R₁ = 15 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    49 V

    Total resistance R₁ + R₂ = 15 + 35 = 50 Ω. Potential difference across R₂ is V_out = (35 ÷ 50) × 70 V = 49 V.

  5. 5. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    24 V

    Total resistance R₁ + R₂ = 3 + 9 = 12 Ω. Potential difference across R₂ is V_out = (9 ÷ 12) × 32 V = 24 V.

  6. 6. In a potential divider circuit connected to a 6 V DC supply, resistor R₁ = 11 Ω and resistor R₂ = 11 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    3 V

    Total resistance R₁ + R₂ = 11 + 11 = 22 Ω. Potential difference across R₂ is V_out = (11 ÷ 22) × 6 V = 3 V.

  7. 7. In a potential divider circuit connected to a 28 V DC supply, resistor R₁ = 11 Ω and resistor R₂ = 33 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    21 V

    Total resistance R₁ + R₂ = 11 + 33 = 44 Ω. Potential difference across R₂ is V_out = (33 ÷ 44) × 28 V = 21 V.

  8. 8. In a potential divider circuit connected to a 42 V DC supply, resistor R₁ = 10 Ω and resistor R₂ = 25 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    30 V

    Total resistance R₁ + R₂ = 10 + 25 = 35 Ω. Potential difference across R₂ is V_out = (25 ÷ 35) × 42 V = 30 V.

  9. 9. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    8 V

    Total resistance R₁ + R₂ = 9 + 9 = 18 Ω. Potential difference across R₂ is V_out = (9 ÷ 18) × 16 V = 8 V.

  10. 10. In a potential divider circuit connected to a 20 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 14 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    14 V

    Total resistance R₁ + R₂ = 6 + 14 = 20 Ω. Potential difference across R₂ is V_out = (14 ÷ 20) × 20 V = 14 V.

  11. 11. In a potential divider circuit connected to a 35 V DC supply, resistor R₁ = 24 Ω and resistor R₂ = 36 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    21 V

    Total resistance R₁ + R₂ = 24 + 36 = 60 Ω. Potential difference across R₂ is V_out = (36 ÷ 60) × 35 V = 21 V.

  12. 12. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 9 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    12 V

    Total resistance R₁ + R₂ = 3 + 9 = 12 Ω. Potential difference across R₂ is V_out = (9 ÷ 12) × 16 V = 12 V.

12 questions · Seed 60 · Age guidance, not curriculum certification