Small practice. Bright discoveries.Explore the free starter collection
Back to worksheets
ScienceAges 16-18

Potential divider circuits

Apply the potential divider equation V_out = (R₂ ÷ (R₁ + R₂)) × V_in across two series resistors connected to a DC source. Review suitability for your learners before teaching.

New variationTry interactive challengeBrowse templates

Choose “Save as PDF” to keep a copy. Use your browser’s paper setting for A4 or Letter.

Worksheet StudioPractice pack · Ages 16-18

Potential divider circuits

Take your time. Show your thinking.

  1. 1. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 5 Ω and resistor R₂ = 5 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 16 V · R₁ = 5 Ω, R₂ = 5 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  2. 2. In a potential divider circuit connected to a 56 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 15 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 56 V · R₁ = 6 Ω, R₂ = 15 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  3. 3. In a potential divider circuit connected to a 45 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 12 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 45 V · R₁ = 3 Ω, R₂ = 12 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  4. 4. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 27 Ω and resistor R₂ = 45 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 24 V · R₁ = 27 Ω, R₂ = 45 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  5. 5. In a potential divider circuit connected to a 90 V DC supply, resistor R₁ = 24 Ω and resistor R₂ = 56 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 90 V · R₁ = 24 Ω, R₂ = 56 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  6. 6. In a potential divider circuit connected to a 64 V DC supply, resistor R₁ = 21 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 64 V · R₁ = 21 Ω, R₂ = 35 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  7. 7. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 7 Ω and resistor R₂ = 14 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 24 V · R₁ = 7 Ω, R₂ = 14 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  8. 8. In a potential divider circuit connected to a 30 V DC supply, resistor R₁ = 18 Ω and resistor R₂ = 27 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 30 V · R₁ = 18 Ω, R₂ = 27 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  9. 9. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 24 V · R₁ = 12 Ω, R₂ = 24 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  10. 10. In a potential divider circuit connected to a 15 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 18 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 15 V · R₁ = 9 Ω, R₂ = 18 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  11. 11. In a potential divider circuit connected to a 27 V DC supply, resistor R₁ = 10 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 27 V · R₁ = 10 Ω, R₂ = 20 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
  12. 12. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 27 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    +−R
    V_in = 32 V · R₁ = 9 Ω, R₂ = 27 Ω · V_out = [R₂ ÷ (R₁ + R₂)] × V_in
12 questions · Seed 53 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

Potential divider circuits

Answers and reasoning. Review before teaching.

  1. 1. In a potential divider circuit connected to a 16 V DC supply, resistor R₁ = 5 Ω and resistor R₂ = 5 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    8 V

    Total resistance R₁ + R₂ = 5 + 5 = 10 Ω. Potential difference across R₂ is V_out = (5 ÷ 10) × 16 V = 8 V.

  2. 2. In a potential divider circuit connected to a 56 V DC supply, resistor R₁ = 6 Ω and resistor R₂ = 15 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    40 V

    Total resistance R₁ + R₂ = 6 + 15 = 21 Ω. Potential difference across R₂ is V_out = (15 ÷ 21) × 56 V = 40 V.

  3. 3. In a potential divider circuit connected to a 45 V DC supply, resistor R₁ = 3 Ω and resistor R₂ = 12 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    36 V

    Total resistance R₁ + R₂ = 3 + 12 = 15 Ω. Potential difference across R₂ is V_out = (12 ÷ 15) × 45 V = 36 V.

  4. 4. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 27 Ω and resistor R₂ = 45 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    15 V

    Total resistance R₁ + R₂ = 27 + 45 = 72 Ω. Potential difference across R₂ is V_out = (45 ÷ 72) × 24 V = 15 V.

  5. 5. In a potential divider circuit connected to a 90 V DC supply, resistor R₁ = 24 Ω and resistor R₂ = 56 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    63 V

    Total resistance R₁ + R₂ = 24 + 56 = 80 Ω. Potential difference across R₂ is V_out = (56 ÷ 80) × 90 V = 63 V.

  6. 6. In a potential divider circuit connected to a 64 V DC supply, resistor R₁ = 21 Ω and resistor R₂ = 35 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    40 V

    Total resistance R₁ + R₂ = 21 + 35 = 56 Ω. Potential difference across R₂ is V_out = (35 ÷ 56) × 64 V = 40 V.

  7. 7. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 7 Ω and resistor R₂ = 14 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    16 V

    Total resistance R₁ + R₂ = 7 + 14 = 21 Ω. Potential difference across R₂ is V_out = (14 ÷ 21) × 24 V = 16 V.

  8. 8. In a potential divider circuit connected to a 30 V DC supply, resistor R₁ = 18 Ω and resistor R₂ = 27 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    18 V

    Total resistance R₁ + R₂ = 18 + 27 = 45 Ω. Potential difference across R₂ is V_out = (27 ÷ 45) × 30 V = 18 V.

  9. 9. In a potential divider circuit connected to a 24 V DC supply, resistor R₁ = 12 Ω and resistor R₂ = 24 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    16 V

    Total resistance R₁ + R₂ = 12 + 24 = 36 Ω. Potential difference across R₂ is V_out = (24 ÷ 36) × 24 V = 16 V.

  10. 10. In a potential divider circuit connected to a 15 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 18 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    10 V

    Total resistance R₁ + R₂ = 9 + 18 = 27 Ω. Potential difference across R₂ is V_out = (18 ÷ 27) × 15 V = 10 V.

  11. 11. In a potential divider circuit connected to a 27 V DC supply, resistor R₁ = 10 Ω and resistor R₂ = 20 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    18 V

    Total resistance R₁ + R₂ = 10 + 20 = 30 Ω. Potential difference across R₂ is V_out = (20 ÷ 30) × 27 V = 18 V.

  12. 12. In a potential divider circuit connected to a 32 V DC supply, resistor R₁ = 9 Ω and resistor R₂ = 27 Ω are connected in series. Using V_out = (R₂ ÷ (R₁ + R₂)) × V_in, calculate the potential difference across R₂.

    24 V

    Total resistance R₁ + R₂ = 9 + 27 = 36 Ω. Potential difference across R₂ is V_out = (27 ÷ 36) × 32 V = 24 V.

12 questions · Seed 53 · Age guidance, not curriculum certification