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MathsAges 16-18

2×2 matrix determinants

Evaluate the determinant det(M) = ad − bc of a 2 × 2 matrix from its leading and secondary diagonals. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

2×2 matrix determinants

Take your time. Show your thinking.

  1. 1. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 10], [9, 3]].

    abcd
    M = [ 11 10 ; 9 3 ] · det(M) = (11×3) − (10×9)
  2. 2. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[9, 2], [10, 4]].

    abcd
    M = [ 9 2 ; 10 4 ] · det(M) = (9×4) − (2×10)
  3. 3. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 5], [5, 8]].

    abcd
    M = [ 11 5 ; 5 8 ] · det(M) = (11×8) − (5×5)
  4. 4. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[7, 4], [6, 6]].

    abcd
    M = [ 7 4 ; 6 6 ] · det(M) = (7×6) − (4×6)
  5. 5. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 2], [2, 10]].

    abcd
    M = [ 11 2 ; 2 10 ] · det(M) = (11×10) − (2×2)
  6. 6. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 2], [9, 10]].

    abcd
    M = [ 4 2 ; 9 10 ] · det(M) = (4×10) − (2×9)
  7. 7. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[3, 2], [2, 7]].

    abcd
    M = [ 3 2 ; 2 7 ] · det(M) = (3×7) − (2×2)
  8. 8. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[6, 1], [7, 3]].

    abcd
    M = [ 6 1 ; 7 3 ] · det(M) = (6×3) − (1×7)
  9. 9. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 6], [8, 7]].

    abcd
    M = [ 4 6 ; 8 7 ] · det(M) = (4×7) − (6×8)
  10. 10. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 3], [9, 12]].

    abcd
    M = [ 11 3 ; 9 12 ] · det(M) = (11×12) − (3×9)
  11. 11. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 2], [10, 2]].

    abcd
    M = [ 2 2 ; 10 2 ] · det(M) = (2×2) − (2×10)
  12. 12. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 3], [4, 4]].

    abcd
    M = [ 2 3 ; 4 4 ] · det(M) = (2×4) − (3×4)
12 questions · Seed 43 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

2×2 matrix determinants

Answers and reasoning. Review before teaching.

  1. 1. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 10], [9, 3]].

    -57

    det(M) = (11 × 3) − (10 × 9) = 33 − 90 = -57.

  2. 2. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[9, 2], [10, 4]].

    16

    det(M) = (9 × 4) − (2 × 10) = 36 − 20 = 16.

  3. 3. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 5], [5, 8]].

    63

    det(M) = (11 × 8) − (5 × 5) = 88 − 25 = 63.

  4. 4. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[7, 4], [6, 6]].

    18

    det(M) = (7 × 6) − (4 × 6) = 42 − 24 = 18.

  5. 5. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 2], [2, 10]].

    106

    det(M) = (11 × 10) − (2 × 2) = 110 − 4 = 106.

  6. 6. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 2], [9, 10]].

    22

    det(M) = (4 × 10) − (2 × 9) = 40 − 18 = 22.

  7. 7. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[3, 2], [2, 7]].

    17

    det(M) = (3 × 7) − (2 × 2) = 21 − 4 = 17.

  8. 8. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[6, 1], [7, 3]].

    11

    det(M) = (6 × 3) − (1 × 7) = 18 − 7 = 11.

  9. 9. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 6], [8, 7]].

    -20

    det(M) = (4 × 7) − (6 × 8) = 28 − 48 = -20.

  10. 10. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 3], [9, 12]].

    105

    det(M) = (11 × 12) − (3 × 9) = 132 − 27 = 105.

  11. 11. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 2], [10, 2]].

    -16

    det(M) = (2 × 2) − (2 × 10) = 4 − 20 = -16.

  12. 12. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 3], [4, 4]].

    -4

    det(M) = (2 × 4) − (3 × 4) = 8 − 12 = -4.

12 questions · Seed 43 · Age guidance, not curriculum certification