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MathsAges 16-18

2×2 matrix determinants

Evaluate the determinant det(M) = ad − bc of a 2 × 2 matrix from its leading and secondary diagonals. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

2×2 matrix determinants

Take your time. Show your thinking.

  1. 1. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[3, 3], [2, 11]].

    abcd
    M = [ 3 3 ; 2 11 ] · det(M) = (3×11) − (3×2)
  2. 2. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 9], [8, 9]].

    abcd
    M = [ 2 9 ; 8 9 ] · det(M) = (2×9) − (9×8)
  3. 3. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[8, 8], [2, 11]].

    abcd
    M = [ 8 8 ; 2 11 ] · det(M) = (8×11) − (8×2)
  4. 4. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[7, 8], [5, 2]].

    abcd
    M = [ 7 8 ; 5 2 ] · det(M) = (7×2) − (8×5)
  5. 5. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 8], [10, 11]].

    abcd
    M = [ 2 8 ; 10 11 ] · det(M) = (2×11) − (8×10)
  6. 6. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[10, 3], [6, 10]].

    abcd
    M = [ 10 3 ; 6 10 ] · det(M) = (10×10) − (3×6)
  7. 7. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 2], [5, 9]].

    abcd
    M = [ 2 2 ; 5 9 ] · det(M) = (2×9) − (2×5)
  8. 8. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[9, 7], [8, 5]].

    abcd
    M = [ 9 7 ; 8 5 ] · det(M) = (9×5) − (7×8)
  9. 9. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 10], [7, 12]].

    abcd
    M = [ 4 10 ; 7 12 ] · det(M) = (4×12) − (10×7)
  10. 10. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 10], [8, 11]].

    abcd
    M = [ 11 10 ; 8 11 ] · det(M) = (11×11) − (10×8)
  11. 11. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 1], [7, 9]].

    abcd
    M = [ 2 1 ; 7 9 ] · det(M) = (2×9) − (1×7)
  12. 12. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 10], [5, 3]].

    abcd
    M = [ 2 10 ; 5 3 ] · det(M) = (2×3) − (10×5)
12 questions · Seed 104738 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

2×2 matrix determinants

Answers and reasoning. Review before teaching.

  1. 1. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[3, 3], [2, 11]].

    27

    det(M) = (3 × 11) − (3 × 2) = 33 − 6 = 27.

  2. 2. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 9], [8, 9]].

    -54

    det(M) = (2 × 9) − (9 × 8) = 18 − 72 = -54.

  3. 3. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[8, 8], [2, 11]].

    72

    det(M) = (8 × 11) − (8 × 2) = 88 − 16 = 72.

  4. 4. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[7, 8], [5, 2]].

    -26

    det(M) = (7 × 2) − (8 × 5) = 14 − 40 = -26.

  5. 5. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 8], [10, 11]].

    -58

    det(M) = (2 × 11) − (8 × 10) = 22 − 80 = -58.

  6. 6. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[10, 3], [6, 10]].

    82

    det(M) = (10 × 10) − (3 × 6) = 100 − 18 = 82.

  7. 7. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 2], [5, 9]].

    8

    det(M) = (2 × 9) − (2 × 5) = 18 − 10 = 8.

  8. 8. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[9, 7], [8, 5]].

    -11

    det(M) = (9 × 5) − (7 × 8) = 45 − 56 = -11.

  9. 9. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[4, 10], [7, 12]].

    -22

    det(M) = (4 × 12) − (10 × 7) = 48 − 70 = -22.

  10. 10. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[11, 10], [8, 11]].

    41

    det(M) = (11 × 11) − (10 × 8) = 121 − 80 = 41.

  11. 11. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 1], [7, 9]].

    11

    det(M) = (2 × 9) − (1 × 7) = 18 − 7 = 11.

  12. 12. Calculate the determinant det(M) = ad − bc of the 2×2 matrix M = [[2, 10], [5, 3]].

    -44

    det(M) = (2 × 3) − (10 × 5) = 6 − 50 = -44.

12 questions · Seed 104738 · Age guidance, not curriculum certification