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ScienceAges 16-18

Boyle’s law & gas compression

Apply Boyle’s law (P₁V₁ = P₂V₂) to calculate the pressure of an ideal gas after isothermal compression. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

Boyle’s law & gas compression

Take your time. Show your thinking.

  1. 1. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 120 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  2. 2. A sealed cylinder contains 30 dm³ of ideal gas at an initial pressure of 105 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 105 kPa, V₁ = 30 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  3. 3. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 180 kPa, V₁ = 18 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  4. 4. A sealed cylinder contains 54 dm³ of ideal gas at an initial pressure of 145 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 145 kPa, V₁ = 54 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  5. 5. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 135 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 135 kPa, V₁ = 90 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  6. 6. A sealed cylinder contains 28 dm³ of ideal gas at an initial pressure of 190 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 190 kPa, V₁ = 28 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  7. 7. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  8. 8. A sealed cylinder contains 26 dm³ of ideal gas at an initial pressure of 80 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 80 kPa, V₁ = 26 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  9. 9. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 170 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 170 kPa, V₁ = 18 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  10. 10. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 220 kPa. The gas is compressed at constant temperature to a volume of 12 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 220 kPa, V₁ = 48 dm³ · Compressed to V₂ = 12 dm³ → P₂ = ?

  11. 11. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 150 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 150 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  12. 12. A sealed cylinder contains 72 dm³ of ideal gas at an initial pressure of 55 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 55 kPa, V₁ = 72 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?
12 questions · Seed 42 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

Boyle’s law & gas compression

Answers and reasoning. Review before teaching.

  1. 1. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    960 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (120 kPa × 104 dm³) ÷ 13 dm³ = 960 kPa.

  2. 2. A sealed cylinder contains 30 dm³ of ideal gas at an initial pressure of 105 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    210 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (105 kPa × 30 dm³) ÷ 15 dm³ = 210 kPa.

  3. 3. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    360 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (180 kPa × 18 dm³) ÷ 9 dm³ = 360 kPa.

  4. 4. A sealed cylinder contains 54 dm³ of ideal gas at an initial pressure of 145 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    870 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (145 kPa × 54 dm³) ÷ 9 dm³ = 870 kPa.

  5. 5. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 135 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    810 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (135 kPa × 90 dm³) ÷ 15 dm³ = 810 kPa.

  6. 6. A sealed cylinder contains 28 dm³ of ideal gas at an initial pressure of 190 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    380 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (190 kPa × 28 dm³) ÷ 14 dm³ = 380 kPa.

  7. 7. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 104 dm³) ÷ 13 dm³ = 1880 kPa.

  8. 8. A sealed cylinder contains 26 dm³ of ideal gas at an initial pressure of 80 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    160 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (80 kPa × 26 dm³) ÷ 13 dm³ = 160 kPa.

  9. 9. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 170 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    510 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (170 kPa × 18 dm³) ÷ 6 dm³ = 510 kPa.

  10. 10. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 220 kPa. The gas is compressed at constant temperature to a volume of 12 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (220 kPa × 48 dm³) ÷ 12 dm³ = 880 kPa.

  11. 11. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 150 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1200 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (150 kPa × 104 dm³) ÷ 13 dm³ = 1200 kPa.

  12. 12. A sealed cylinder contains 72 dm³ of ideal gas at an initial pressure of 55 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    440 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (55 kPa × 72 dm³) ÷ 9 dm³ = 440 kPa.

12 questions · Seed 42 · Age guidance, not curriculum certification
Worksheet StudioPractice pack · Ages 16-18

Boyle’s law & gas compression

Take your time. Show your thinking.

  1. 1. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 120 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  2. 2. A sealed cylinder contains 30 dm³ of ideal gas at an initial pressure of 105 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 105 kPa, V₁ = 30 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  3. 3. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 180 kPa, V₁ = 18 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  4. 4. A sealed cylinder contains 54 dm³ of ideal gas at an initial pressure of 145 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 145 kPa, V₁ = 54 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  5. 5. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 135 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 135 kPa, V₁ = 90 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  6. 6. A sealed cylinder contains 28 dm³ of ideal gas at an initial pressure of 190 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 190 kPa, V₁ = 28 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  7. 7. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  8. 8. A sealed cylinder contains 26 dm³ of ideal gas at an initial pressure of 80 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 80 kPa, V₁ = 26 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  9. 9. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 170 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 170 kPa, V₁ = 18 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  10. 10. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 220 kPa. The gas is compressed at constant temperature to a volume of 12 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 220 kPa, V₁ = 48 dm³ · Compressed to V₂ = 12 dm³ → P₂ = ?

  11. 11. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 150 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 150 kPa, V₁ = 104 dm³ · Compressed to V₂ = 13 dm³ → P₂ = ?

  12. 12. A sealed cylinder contains 72 dm³ of ideal gas at an initial pressure of 55 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 55 kPa, V₁ = 72 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?
12 questions · Seed 42 · Age guidance, not curriculum certification
Worksheet StudioAnswer key · Ages 16-18

Boyle’s law & gas compression

Answers and reasoning. Review before teaching.

  1. 1. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    960 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (120 kPa × 104 dm³) ÷ 13 dm³ = 960 kPa.

  2. 2. A sealed cylinder contains 30 dm³ of ideal gas at an initial pressure of 105 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    210 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (105 kPa × 30 dm³) ÷ 15 dm³ = 210 kPa.

  3. 3. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    360 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (180 kPa × 18 dm³) ÷ 9 dm³ = 360 kPa.

  4. 4. A sealed cylinder contains 54 dm³ of ideal gas at an initial pressure of 145 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    870 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (145 kPa × 54 dm³) ÷ 9 dm³ = 870 kPa.

  5. 5. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 135 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    810 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (135 kPa × 90 dm³) ÷ 15 dm³ = 810 kPa.

  6. 6. A sealed cylinder contains 28 dm³ of ideal gas at an initial pressure of 190 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    380 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (190 kPa × 28 dm³) ÷ 14 dm³ = 380 kPa.

  7. 7. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 104 dm³) ÷ 13 dm³ = 1880 kPa.

  8. 8. A sealed cylinder contains 26 dm³ of ideal gas at an initial pressure of 80 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    160 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (80 kPa × 26 dm³) ÷ 13 dm³ = 160 kPa.

  9. 9. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 170 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    510 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (170 kPa × 18 dm³) ÷ 6 dm³ = 510 kPa.

  10. 10. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 220 kPa. The gas is compressed at constant temperature to a volume of 12 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (220 kPa × 48 dm³) ÷ 12 dm³ = 880 kPa.

  11. 11. A sealed cylinder contains 104 dm³ of ideal gas at an initial pressure of 150 kPa. The gas is compressed at constant temperature to a volume of 13 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1200 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (150 kPa × 104 dm³) ÷ 13 dm³ = 1200 kPa.

  12. 12. A sealed cylinder contains 72 dm³ of ideal gas at an initial pressure of 55 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    440 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (55 kPa × 72 dm³) ÷ 9 dm³ = 440 kPa.

12 questions · Seed 42 · Age guidance, not curriculum certification