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ScienceAges 13-15

Boyle’s law & gas compression

Apply Boyle’s law (P₁V₁ = P₂V₂) to calculate the pressure of an ideal gas after isothermal compression. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 13-15

Boyle’s law & gas compression

Take your time. Show your thinking.

  1. 1. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 3 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 180 kPa, V₁ = 18 dm³ · Compressed to V₂ = 3 dm³ → P₂ = ?

  2. 2. A sealed cylinder contains 60 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 125 kPa, V₁ = 60 dm³ · Compressed to V₂ = 10 dm³ → P₂ = ?

  3. 3. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 48 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  4. 4. A sealed cylinder contains 45 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 120 kPa, V₁ = 45 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  5. 5. A sealed cylinder contains 112 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 75 kPa, V₁ = 112 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  6. 6. A sealed cylinder contains 75 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 75 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  7. 7. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 275 kPa. The gas is compressed at constant temperature to a volume of 4 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 275 kPa, V₁ = 20 dm³ · Compressed to V₂ = 4 dm³ → P₂ = ?

  8. 8. A sealed cylinder contains 24 dm³ of ideal gas at an initial pressure of 65 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 65 kPa, V₁ = 24 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  9. 9. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 125 kPa, V₁ = 90 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  10. 10. A sealed cylinder contains 12 dm³ of ideal gas at an initial pressure of 175 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 175 kPa, V₁ = 12 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  11. 11. A sealed cylinder contains 70 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 75 kPa, V₁ = 70 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  12. 12. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 115 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 115 kPa, V₁ = 20 dm³ · Compressed to V₂ = 10 dm³ → P₂ = ?
12 questions · Seed 43 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 13-15

Boyle’s law & gas compression

Answers and reasoning. Review before teaching.

  1. 1. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 3 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1080 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (180 kPa × 18 dm³) ÷ 3 dm³ = 1080 kPa.

  2. 2. A sealed cylinder contains 60 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    750 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (125 kPa × 60 dm³) ÷ 10 dm³ = 750 kPa.

  3. 3. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 48 dm³) ÷ 6 dm³ = 1880 kPa.

  4. 4. A sealed cylinder contains 45 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    600 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (120 kPa × 45 dm³) ÷ 9 dm³ = 600 kPa.

  5. 5. A sealed cylinder contains 112 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    600 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (75 kPa × 112 dm³) ÷ 14 dm³ = 600 kPa.

  6. 6. A sealed cylinder contains 75 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1175 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 75 dm³) ÷ 15 dm³ = 1175 kPa.

  7. 7. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 275 kPa. The gas is compressed at constant temperature to a volume of 4 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1375 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (275 kPa × 20 dm³) ÷ 4 dm³ = 1375 kPa.

  8. 8. A sealed cylinder contains 24 dm³ of ideal gas at an initial pressure of 65 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    260 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (65 kPa × 24 dm³) ÷ 6 dm³ = 260 kPa.

  9. 9. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    750 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (125 kPa × 90 dm³) ÷ 15 dm³ = 750 kPa.

  10. 10. A sealed cylinder contains 12 dm³ of ideal gas at an initial pressure of 175 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    350 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (175 kPa × 12 dm³) ÷ 6 dm³ = 350 kPa.

  11. 11. A sealed cylinder contains 70 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    375 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (75 kPa × 70 dm³) ÷ 14 dm³ = 375 kPa.

  12. 12. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 115 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    230 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (115 kPa × 20 dm³) ÷ 10 dm³ = 230 kPa.

12 questions · Seed 43 · Age guidance, not curriculum certification
Worksheet StudioPractice pack · Ages 13-15

Boyle’s law & gas compression

Take your time. Show your thinking.

  1. 1. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 3 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 180 kPa, V₁ = 18 dm³ · Compressed to V₂ = 3 dm³ → P₂ = ?

  2. 2. A sealed cylinder contains 60 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 125 kPa, V₁ = 60 dm³ · Compressed to V₂ = 10 dm³ → P₂ = ?

  3. 3. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 48 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  4. 4. A sealed cylinder contains 45 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 120 kPa, V₁ = 45 dm³ · Compressed to V₂ = 9 dm³ → P₂ = ?

  5. 5. A sealed cylinder contains 112 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 75 kPa, V₁ = 112 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  6. 6. A sealed cylinder contains 75 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 235 kPa, V₁ = 75 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  7. 7. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 275 kPa. The gas is compressed at constant temperature to a volume of 4 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 275 kPa, V₁ = 20 dm³ · Compressed to V₂ = 4 dm³ → P₂ = ?

  8. 8. A sealed cylinder contains 24 dm³ of ideal gas at an initial pressure of 65 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 65 kPa, V₁ = 24 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  9. 9. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 125 kPa, V₁ = 90 dm³ · Compressed to V₂ = 15 dm³ → P₂ = ?

  10. 10. A sealed cylinder contains 12 dm³ of ideal gas at an initial pressure of 175 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 175 kPa, V₁ = 12 dm³ · Compressed to V₂ = 6 dm³ → P₂ = ?

  11. 11. A sealed cylinder contains 70 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 75 kPa, V₁ = 70 dm³ · Compressed to V₂ = 14 dm³ → P₂ = ?

  12. 12. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 115 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    P₁ = 115 kPa, V₁ = 20 dm³ · Compressed to V₂ = 10 dm³ → P₂ = ?
12 questions · Seed 43 · Age guidance, not curriculum certification
Worksheet StudioAnswer key · Ages 13-15

Boyle’s law & gas compression

Answers and reasoning. Review before teaching.

  1. 1. A sealed cylinder contains 18 dm³ of ideal gas at an initial pressure of 180 kPa. The gas is compressed at constant temperature to a volume of 3 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1080 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (180 kPa × 18 dm³) ÷ 3 dm³ = 1080 kPa.

  2. 2. A sealed cylinder contains 60 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    750 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (125 kPa × 60 dm³) ÷ 10 dm³ = 750 kPa.

  3. 3. A sealed cylinder contains 48 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1880 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 48 dm³) ÷ 6 dm³ = 1880 kPa.

  4. 4. A sealed cylinder contains 45 dm³ of ideal gas at an initial pressure of 120 kPa. The gas is compressed at constant temperature to a volume of 9 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    600 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (120 kPa × 45 dm³) ÷ 9 dm³ = 600 kPa.

  5. 5. A sealed cylinder contains 112 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    600 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (75 kPa × 112 dm³) ÷ 14 dm³ = 600 kPa.

  6. 6. A sealed cylinder contains 75 dm³ of ideal gas at an initial pressure of 235 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1175 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (235 kPa × 75 dm³) ÷ 15 dm³ = 1175 kPa.

  7. 7. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 275 kPa. The gas is compressed at constant temperature to a volume of 4 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    1375 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (275 kPa × 20 dm³) ÷ 4 dm³ = 1375 kPa.

  8. 8. A sealed cylinder contains 24 dm³ of ideal gas at an initial pressure of 65 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    260 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (65 kPa × 24 dm³) ÷ 6 dm³ = 260 kPa.

  9. 9. A sealed cylinder contains 90 dm³ of ideal gas at an initial pressure of 125 kPa. The gas is compressed at constant temperature to a volume of 15 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    750 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (125 kPa × 90 dm³) ÷ 15 dm³ = 750 kPa.

  10. 10. A sealed cylinder contains 12 dm³ of ideal gas at an initial pressure of 175 kPa. The gas is compressed at constant temperature to a volume of 6 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    350 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (175 kPa × 12 dm³) ÷ 6 dm³ = 350 kPa.

  11. 11. A sealed cylinder contains 70 dm³ of ideal gas at an initial pressure of 75 kPa. The gas is compressed at constant temperature to a volume of 14 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    375 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (75 kPa × 70 dm³) ÷ 14 dm³ = 375 kPa.

  12. 12. A sealed cylinder contains 20 dm³ of ideal gas at an initial pressure of 115 kPa. The gas is compressed at constant temperature to a volume of 10 dm³. Using Boyle’s law (P₁V₁ = P₂V₂), calculate the final pressure.

    230 kPa

    By Boyle’s law at constant temperature, P₂ = (P₁ × V₁) ÷ V₂ = (115 kPa × 20 dm³) ÷ 10 dm³ = 230 kPa.

12 questions · Seed 43 · Age guidance, not curriculum certification