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MathsAges 16-18

Chain rule differentiation

Apply the chain rule to differentiate composite power functions f(x) = (ax + b)ⁿ and evaluate at a given x. Review suitability for your learners before teaching.

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Worksheet StudioPractice pack · Ages 16-18

Chain rule differentiation

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  1. 1. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(3).

    f(x) = (4x + 7)^2 · f′(3) at u = 19
  2. 2. Using the chain rule, differentiate f(x) = (3x + 1)^2 and evaluate f′(1).

    f(x) = (3x + 1)^2 · f′(1) at u = 4
  3. 3. Using the chain rule, differentiate f(x) = (4x + 2)^2 and evaluate f′(1).

    f(x) = (4x + 2)^2 · f′(1) at u = 6
  4. 4. Using the chain rule, differentiate f(x) = (3x + 4)^2 and evaluate f′(2).

    f(x) = (3x + 4)^2 · f′(2) at u = 10
  5. 5. Using the chain rule, differentiate f(x) = (4x + 3)^3 and evaluate f′(3).

    f(x) = (4x + 3)^3 · f′(3) at u = 15
  6. 6. Using the chain rule, differentiate f(x) = (5x + 3)^4 and evaluate f′(4).

    f(x) = (5x + 3)^4 · f′(4) at u = 23
  7. 7. Using the chain rule, differentiate f(x) = (3x + 8)^2 and evaluate f′(3).

    f(x) = (3x + 8)^2 · f′(3) at u = 17
  8. 8. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(1).

    f(x) = (4x + 7)^2 · f′(1) at u = 11
  9. 9. Using the chain rule, differentiate f(x) = (6x + 8)^2 and evaluate f′(1).

    f(x) = (6x + 8)^2 · f′(1) at u = 14
  10. 10. Using the chain rule, differentiate f(x) = (4x + 2)^2 and evaluate f′(2).

    f(x) = (4x + 2)^2 · f′(2) at u = 10
  11. 11. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(4).

    f(x) = (4x + 7)^2 · f′(4) at u = 23
  12. 12. Using the chain rule, differentiate f(x) = (3x + 5)^2 and evaluate f′(4).

    f(x) = (3x + 5)^2 · f′(4) at u = 17
12 questions · Seed 45 · Age guidance, not curriculum certification
View the answer key
Worksheet StudioAnswer key · Ages 16-18

Chain rule differentiation

Answers and reasoning. Review before teaching.

  1. 1. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(3).

    152

    By the chain rule, f′(x) = 2 × 4(4x + 7)^1 = 8(4x + 7)^1. At x = 3, f′(3) = 8 × 19^1 = 152.

  2. 2. Using the chain rule, differentiate f(x) = (3x + 1)^2 and evaluate f′(1).

    24

    By the chain rule, f′(x) = 2 × 3(3x + 1)^1 = 6(3x + 1)^1. At x = 1, f′(1) = 6 × 4^1 = 24.

  3. 3. Using the chain rule, differentiate f(x) = (4x + 2)^2 and evaluate f′(1).

    48

    By the chain rule, f′(x) = 2 × 4(4x + 2)^1 = 8(4x + 2)^1. At x = 1, f′(1) = 8 × 6^1 = 48.

  4. 4. Using the chain rule, differentiate f(x) = (3x + 4)^2 and evaluate f′(2).

    60

    By the chain rule, f′(x) = 2 × 3(3x + 4)^1 = 6(3x + 4)^1. At x = 2, f′(2) = 6 × 10^1 = 60.

  5. 5. Using the chain rule, differentiate f(x) = (4x + 3)^3 and evaluate f′(3).

    2700

    By the chain rule, f′(x) = 3 × 4(4x + 3)^2 = 12(4x + 3)^2. At x = 3, f′(3) = 12 × 15^2 = 2700.

  6. 6. Using the chain rule, differentiate f(x) = (5x + 3)^4 and evaluate f′(4).

    243340

    By the chain rule, f′(x) = 4 × 5(5x + 3)^3 = 20(5x + 3)^3. At x = 4, f′(4) = 20 × 23^3 = 243340.

  7. 7. Using the chain rule, differentiate f(x) = (3x + 8)^2 and evaluate f′(3).

    102

    By the chain rule, f′(x) = 2 × 3(3x + 8)^1 = 6(3x + 8)^1. At x = 3, f′(3) = 6 × 17^1 = 102.

  8. 8. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(1).

    88

    By the chain rule, f′(x) = 2 × 4(4x + 7)^1 = 8(4x + 7)^1. At x = 1, f′(1) = 8 × 11^1 = 88.

  9. 9. Using the chain rule, differentiate f(x) = (6x + 8)^2 and evaluate f′(1).

    168

    By the chain rule, f′(x) = 2 × 6(6x + 8)^1 = 12(6x + 8)^1. At x = 1, f′(1) = 12 × 14^1 = 168.

  10. 10. Using the chain rule, differentiate f(x) = (4x + 2)^2 and evaluate f′(2).

    80

    By the chain rule, f′(x) = 2 × 4(4x + 2)^1 = 8(4x + 2)^1. At x = 2, f′(2) = 8 × 10^1 = 80.

  11. 11. Using the chain rule, differentiate f(x) = (4x + 7)^2 and evaluate f′(4).

    184

    By the chain rule, f′(x) = 2 × 4(4x + 7)^1 = 8(4x + 7)^1. At x = 4, f′(4) = 8 × 23^1 = 184.

  12. 12. Using the chain rule, differentiate f(x) = (3x + 5)^2 and evaluate f′(4).

    102

    By the chain rule, f′(x) = 2 × 3(3x + 5)^1 = 6(3x + 5)^1. At x = 4, f′(4) = 6 × 17^1 = 102.

12 questions · Seed 45 · Age guidance, not curriculum certification